document.write( "Question 269827: Please help me solve using completing the square: $\"+t%5E2-8t%2B40=0+\"$ \n" ); document.write( "

Algebra.Com's Answer #197690 by Earlsdon(6294) $\"\"$ $\"About$

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Solve by completing the square:
\n" ); document.write( " $\"t%5E2-8t%2B40+=+0\"$ Subtract 40 from both sides.
\n" ); document.write( " $\"t%5E2-8t+=+-40\"$ Now add the square of half the coefficient of the t-term to both sides. This is $\"%28-8%2F2%29%5E2+=+16\"$
\n" ); document.write( " $\"t%5E2-8t%2B16+=+-40%2B16\"$ Simplify.
\n" ); document.write( " $\"%28t-4%29%5E2+=+-24\"$ Take the square root of both sides.
\n" ); document.write( " $\"t-4+=+sqrt%28-24%29\"$ or $\"t-4+=+-sqrt%28-24%29\"$ Add 4 to both sides of each solution.
\n" ); document.write( " $\"t+=+4%2Bsqrt%28-24%29\"$ or $\"t+=+4-sqrt%28-24%29\"$ This could be further simplified to:
\n" ); document.write( " $\"t+=+4%2B2sqrt%28-6%29\"$ or $\"t+=+4-2sqrt%28-6%29\"$ \n" ); document.write( "

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