document.write( "Question 269831: A freight train and an express train leave towns 390km apart, traveling toward one another. The freight train travels 30km per hr slower than the express train. They pass one another 3 hr later. What are their speeds? \n" ); document.write( "
Algebra.Com's Answer #197684 by drk(1908)\"\" \"About 
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This is an RTD problem. Here is a table based on the given information
\n" ); document.write( "trains . . . . . . . . .rate . . . . . . . . .time . . . . . . . . .distance
\n" ); document.write( "freight. . . . . . . . r - 30 . . . . . . . . .3 . . . . . . . . . . 3r - 90
\n" ); document.write( "express. . . . . . . .r . . . . . . . . . . . . 3 . . . . . . . . . . . 3r
\n" ); document.write( "totals. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .390
\n" ); document.write( "Look at the last column, we get
\n" ); document.write( "\"3r+-+90+%2B+3r+=+390\"
\n" ); document.write( "simplify to get
\n" ); document.write( "\"6r+-+90+=+380\"
\n" ); document.write( "add 90 to get
\n" ); document.write( "\"6r+=+480\"
\n" ); document.write( "divide to get
\n" ); document.write( "express: \"r+=+80\"
\n" ); document.write( "freight: \"r-30+=+50\"
\n" ); document.write( "
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