document.write( "Question 269710: A man's boyhood lasted 1/6 of his life,he played football for the next 1/8 of his life and married five years after quitting football. a daughter was born after he had been married 1/12 of his life. the daughter lived 1/2 as many years as her father. the man died 6 years after his daughter. use a number line. then write an equation and solve \n" ); document.write( "
Algebra.Com's Answer #197640 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( "boyhood = \n" ); document.write( "years played football = \n" ); document.write( "years between football and marriage = \n" ); document.write( "years after marriage daughter was born = \n" ); document.write( "years Daughter was alive = \n" ); document.write( "years after daughter died that man died = \n" ); document.write( "------------------------------------------------------ \n" ); document.write( "All of this added together is the man's whole lifetime, so \n" ); document.write( " \n" ); document.write( "Multiply both sides of equation by \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The man lived to be 88 years old \n" ); document.write( "check: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK \n" ); document.write( " |