document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=269703>Question 269703</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I thought I new what I was doing, maybe I'm just tired. I created a system of 2 equations to find length and width and tried to substitute and solve. Please go over the steps and equations used.\r<BR>\n" );
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document.write( "A rectangular lot whose perimeter is 220 feet is fenced along three sides.  An expensive fencing along the lot's length  costs $20 per foot, and an inexpensive fencing along the two side widths costs only $8 per foot.  The total cost of the fencing along the three sides comes to $2040.  What are the lot's dimensions? \r<BR>\n" );
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document.write( "-Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #197623 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=197623\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A rectangular lot whose perimeter is 220 feet is fenced along three sides.  An expensive fencing along the lot's length  costs $20 per foot, and an inexpensive fencing along the two side widths costs only $8 per foot.  The total cost of the fencing along the three sides comes to $2040.  What are the lot's dimensions? \r<BR>\n" );
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document.write( "Let the length be x\r<BR>\n" );
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document.write( "the sum of two lengths will be 2x\r<BR>\n" );
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document.write( "The two widths together will be 220-2x\r<BR>\n" );
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document.write( "the cost for one length will be $20 * x\r<BR>\n" );
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document.write( "and the cost for two widths will be $8* (220-x)\r<BR>\n" );
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document.write( "The total cost is $2040\r<BR>\n" );
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document.write( "So, 20x+8(220-x)= 2040\r<BR>\n" );
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document.write( "20x+1760-8x=2040\r<BR>\n" );
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document.write( "12x=2040-1760\r<BR>\n" );
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document.write( "12x=280\r<BR>\n" );
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document.write( "x= 280/12\r<BR>\n" );
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document.write( "x= 23.33  feet  which is the length\r<BR>\n" );
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document.write( "Substitute the value of x in the term 220-2x \r<BR>\n" );
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document.write( "220-2*23.33\r<BR>\n" );
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document.write( "220-46.66= 173.34 which is sum of two widths.\r<BR>\n" );
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document.write( "dividing by 2 we get 86.67 feet which is measurement of one width.\r<BR>\n" );
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document.write( "23.33 feet  is the length<BR>\n" );
document.write( "86.67 feet which is the width.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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