document.write( "Question 269644: A survey of 300 fatal accidents showed that 123 were alcohol related. Find the point estimate for the population proportion, the margin of error for a 98% confidence and then construct to the 98% confidence interval for the population proportion p. \r
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document.write( "a. Find the margin of error E.
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document.write( " Round E to three decimal places\r
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document.write( "b. Construct a 95% confidence interval for the population proportion p of all Twinkle bulbs.
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Algebra.Com's Answer #197614 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A survey of 300 fatal accidents showed that 123 were alcohol related. \n" ); document.write( "Find the point estimate for the population proportion, \n" ); document.write( "Ans: 123/300 = 0.41 \n" ); document.write( "----------------------- \n" ); document.write( "the margin of error for a 98% confidence \n" ); document.write( "E = invNorm(0.99)sqrt(0.41*0.59/300) = 2.3263*0.284 = 0.0661 \n" ); document.write( "---------------------------------- \n" ); document.write( "and then construct the 98% confidence interval for the population proportion p. \n" ); document.write( "CI: 0.41-0.0661 < p < 0.41+0.0661 \n" ); document.write( "------------------------------------ \n" ); document.write( "Follow the procedure above to answer \"a\" and \"b\" below. \n" ); document.write( "--- \n" ); document.write( "cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================================= \n" ); document.write( "a. Find the margin of error E. \n" ); document.write( "Round E to three decimal places \n" ); document.write( "b. Construct a 95% confidence interval for the population proportion p of all Twinkle bulbs. \n" ); document.write( " |