document.write( "Question 33398: find four consescutive odd integers if the product of the two smaller integers is 112 less than product of the two larger integers. \n" ); document.write( "

Algebra.Com's Answer #19761 by mszlmb(115) $\"\"$ $\"About$

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SWEET a challenge!
\n" ); document.write( "ok so 4 consecutive odd integers whence A*B=C*D-112 and A < B < C < D. let's c..
\n" ); document.write( "D=C+2=B+4=A+6 (cuz they're all odd and consecutive)
\n" ); document.write( "therefore (by substitution)
\n" ); document.write( "(D-6)*(D-4)=(D-2)*(D)-112 ..cool!
\n" ); document.write( "move a couple things from here to there and
\n" ); document.write( "((D-6)*(D-4))-((D-2)*(D))=-112
\n" ); document.write( "so far $\"%28D%5E2-10D%2B24%29-%28D%5E2-2D%29=-112\"$ subtract them and u get
\n" ); document.write( "-8D+24=112 simple algebra from here..
\n" ); document.write( "minus 24 on both sides: -8D=-112-24 .: -8D=-136 divide both sides by -8 and D=17.
\n" ); document.write( "well if D=17, C=15, B=13, and A=11
\n" ); document.write( "let's check: 17*15= 17*3*5= 51*5= 255 and 13*11=143. 255-143=112
\n" ); document.write( ":)))
\n" ); document.write( "if u have any questions don't hesitate to IM me \n" ); document.write( "

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