document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=269580>Question 269580</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you help me solve the problem 2-6y-9y < 92 using the addition and multiplication principles? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #197585 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=197585\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2-6y-9y < 92<BR>\n" );
document.write( "-15Y<92-2<BR>\n" );
document.write( "-15Y<90<BR>\n" );
document.write( "Y>90/-15 [NOTE: THE SIGN CHANGES WHEN DIVIDING BY A NEGATIVE VALUE.]<BR>\n" );
document.write( "Y>-6 ANS.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "LET Y=-5.9<BR>\n" );
document.write( "2-6*-5.9-9*-5.9<92<BR>\n" );
document.write( "2+35.4+53.1<92<BR>\n" );
document.write( "90.5<92 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );