document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=269601>Question 269601</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two sides of a triangle have the same length. The third side measures 2m less than twice the common length. The perimeter of the triangle is 22m. What are the lengths of the three sides? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #197576 by </B><A HREF=/tutors/aboutme.mpl?userid=ninadbhat><B>ninadbhat(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ninadbhat><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=197576\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the length of the common side. Then, the length of the third side is 2x-2 because it is 2 meters less than twice the common side. Therefore you get<BR>\n" );
document.write( "x+x+(2x-2)=22<BR>\n" );
document.write( "2x+2x-2=22<BR>\n" );
document.write( "4x=24<BR>\n" );
document.write( "x=6<BR>\n" );
document.write( "Then, by substitution<BR>\n" );
document.write( "2(6)-2=?<BR>\n" );
document.write( "12-2=10<BR>\n" );
document.write( "Thus, the length of the common side is 6 and the length of the third side is 10.<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "6+6+10=22(?)<BR>\n" );
document.write( "22=22 True </SPAN>\n" );
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