document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=269585>Question 269585</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A northbound train and a southbound train meet each other on parallel tracks heading in opposite directions. The northbound train travels 12 miles per hour faster than the southbound train. After 1.5 hours, they are 201 miles apart. At what speeds are the two trains traveling? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #197573 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=197573\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "201=(X+X+12)1.5<BR>\n" );
document.write( "201=(2X+12)1.5<BR>\n" );
document.write( "201=3X+18<BR>\n" );
document.write( "3X=201-18<BR>\n" );
document.write( "3X=183<BR>\n" );
document.write( "X=183/3<BR>\n" );
document.write( "X=61 MPH IS THE SPEED OF THE SLOWER TRAIN.<BR>\n" );
document.write( "61+12=73 MPH FOR THE FASTER TRAIN.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "201=(61+73)*1.5<BR>\n" );
document.write( "201=134*1.5<BR>\n" );
document.write( "201=201 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );