document.write( "Question 269564: (6/y+4)+1=(5/2y+8)\r
\n" ); document.write( "\n" ); document.write( "I thought that the next step would look like:\r
\n" ); document.write( "\n" ); document.write( "6(2y+8)+(y+4)(2y+8)=5(y+4) but the answer in the back of the book does not
\n" ); document.write( " correspond with this once I finish solving it.
\n" ); document.write( " The final answer should be -15/2. \n" ); document.write( "
Algebra.Com's Answer #197549 by Alan3354(69443)\"\" \"About 
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6/y+4)+1=(5/2y+8)
\n" ); document.write( "I thought that the next step would look like:
\n" ); document.write( "6(2y+8)+(y+4)(2y+8)=5(y+4) but the answer in the back of the book does not
\n" ); document.write( "correspond with this once I finish solving it.
\n" ); document.write( "The final answer should be -15/2.
\n" ); document.write( "----------------
\n" ); document.write( "The DEN of the right side is 2x the one on the left.
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\n" ); document.write( "6/y+4)+1=(5/2y+8)
\n" ); document.write( "Multiply all terms by the right side DEN 2y+8
\n" ); document.write( "12 + 2y+8 = 5
\n" ); document.write( "2y + 20 = 5
\n" ); document.write( "2y = -15
\n" ); document.write( "y = -15/2
\n" ); document.write( " \n" ); document.write( "
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