document.write( "Question 33399: 
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document.write( "7Ö3 - 5Ö75
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Algebra.Com's Answer #19752 by AnlytcPhil(1806)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "7Ö3 - 5Ö75\r\n" );
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document.write( "Break 75 into its prime factors: \r\n" );
document.write( "75 = 3·25 = 3·5·5 = 3·5²,\r\n" );
document.write( "so replace 75 by 3·5²\r\n" );
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document.write( "7V3 - 5Ö3·5²\r\n" );
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document.write( "Take individual square roots of 3 and of 5²:\r\n" );
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document.write( "7Ö3 - 5Ö3·Ö5²\r\n" );
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document.write( "The square root of 5² is just 5\r\n" );
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document.write( "7Ö3 - 5Ö3·(5)\r\n" );
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document.write( "7Ö3 - 25Ö3\r\n" );
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document.write( "Factor out Ö3\r\n" );
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document.write( "Ö3(7 - 25)\r\n" );
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document.write( "Combine what's in the parentheses\r\n" );
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document.write( "Ö3(-18)\r\n" );
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document.write( "-18Ö3\r\n" );
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document.write( "Edwin\r\n" );
document.write( "AnlytcPhil@aol.com
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