document.write( "Question 4028: (x+1)^(-3/2)=8\r
\n" ); document.write( "\n" ); document.write( "Solve the complex solution \n" ); document.write( "
Algebra.Com's Answer #1975 by khwang(438)\"\" \"About 
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\n" ); document.write( " On way
\n" ); document.write( " (x+1)^(-3/2)=8
\n" ); document.write( " [(x+1)^(-1/2)]3 = 2^3,
\n" ); document.write( " So, (x+1)^(-1/2) = 2.
\n" ); document.write( " Square on both sides:
\n" ); document.write( " (x+1)^(-1) = 4,
\n" ); document.write( " Or 1/(x+1) = 4,
\n" ); document.write( " So, (x+1) = 1/4,
\n" ); document.write( " x = -3/4.\r
\n" ); document.write( "\n" ); document.write( " Another way:
\n" ); document.write( " Square on both sides:
\n" ); document.write( " (x+1)^(-3) = 8^2 = 64 = 2^6,
\n" ); document.write( " Take cubic root on both sides:
\n" ); document.write( " (x+1)^(-1) = (2^6)^(1/3) = 2^2 =4,
\n" ); document.write( " So, x+1 = 1/4, x = -3/4\r
\n" ); document.write( "\n" ); document.write( " Check (-3/4 + 1)^(-3/2) = (1/4)^(-3/2) = (1/2)^2*(-3/2)
\n" ); document.write( " = (1/2)^(-3) = [(1/2)^(-1)]^3
\n" ); document.write( " = 2^3 = 8 (correct)\r
\n" ); document.write( "\n" ); document.write( " Kenny \n" ); document.write( "
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