document.write( "Question 269355: A large watermelon weighs 20 kg with 98% of its weight being water. It is left to stand in the sun and some of the water evaporates so that now only 95% of its weight is water. What is its reduced weight?\r
\n" ); document.write( "\n" ); document.write( "(A)17 kg (B) 19.4 kg (C) 10 kg (D) 8 kg (E) None of these.\r
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Algebra.Com's Answer #197427 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A large watermelon weighs 20 kg with 98% of its weight being water. It is left to stand in the sun and some of the water evaporates so that now only 95% of its weight is water. What is its reduced weight?
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\n" ); document.write( "amt of water before drying: 0.98*20 = 19.6 kg
\n" ); document.write( "non-water weight of the melon: 0.4 kg
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\n" ); document.write( "After drying:
\n" ); document.write( "Let weight be \"x\".
\n" ); document.write( "Equation:
\n" ); document.write( "The non-water material in the melon is now 5% of its weight.
\n" ); document.write( "0.05x = 0.4 kg
\n" ); document.write( "x = 8 kg
\n" ); document.write( "The melon now weighs 8 kg.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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\n" ); document.write( "(A)17 kg (B) 19.4 kg (C) 10 kg (D) 8 kg (E) None of these.
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