document.write( "Question 269353: Chandra spent 2/5 of her income of January for rent, and 3/4 of the remainder on other expenses.If she put the remaining $180 in her savings account, how much was her income in January?\r
\n" );
document.write( "\n" );
document.write( "(A)$1,000 (B) $1,200 (C) $1,400 (D) $ 1,600 (E) None of these.
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #197421 by mananth(16949) You can put this solution on YOUR website! Chandra spent 2/5 of her income of January for rent, and 3/4 of the remainder on other expenses.If she put the remaining $180 in her savings account, how much was her income in January?\r \n" ); document.write( "\n" ); document.write( "let the income be x\r \n" ); document.write( "\n" ); document.write( "rent 2/5 *x \n" ); document.write( "remaing amount = 3/4(x- 2/5*x)\r \n" ); document.write( "\n" ); document.write( "2/5 *x + 3/4(x-2/5*x) +180 =x\r \n" ); document.write( "\n" ); document.write( "2/5*x +3/4* (5x-2x/5) +180= x\r \n" ); document.write( "\n" ); document.write( "2x/5 + 9x/20 +180=x\r \n" ); document.write( "\n" ); document.write( "(8x+9x-20x)/20= -180\r \n" ); document.write( "\n" ); document.write( "-3x= -3600\r \n" ); document.write( "\n" ); document.write( "x= -3600/-3 = 1200\r \n" ); document.write( "\n" ); document.write( "the income is $1200\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |