document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=33243>Question 33243</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Norma invested the start-up capital for her Internet business in two hedge funds.  After one year one of the funds returned 5% and the other returned 6% for a total return of $5880.  If the amount on which she made 6% was $10,000 larger than the amount on which she made 5%, then what was the original amount of her start-up capital?   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19739 by </B><A HREF=/tutors/aboutme.mpl?userid=Fermat><B>Fermat(136)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fermat><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fermat><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19739\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let A be the amount invested at 5%.<BR>\n" );
document.write( "Let B be the amount invested at 6%.<BR>\n" );
document.write( "return on A is 0.05A<BR>\n" );
document.write( "return on B is 0.06B<BR>\n" );
document.write( "total return is $5,880<BR>\n" );
document.write( ".: 0.05A + 0.06B = 5880 -----------------(1)<BR>\n" );
document.write( "B is greater than A by $10,000, i,e.<BR>\n" );
document.write( "B = A + 10000<BR>\n" );
document.write( "0.06B = 0.06A + 600 ---------------------(2)<BR>\n" );
document.write( "substituting for B, from (2), into (1),<BR>\n" );
document.write( "0.05A + 0.06A + 600 = 5880<BR>\n" );
document.write( "0.11A = 5280<BR>\n" );
document.write( "A = 48000<BR>\n" );
document.write( "B = 58000<BR>\n" );
document.write( "Total Startup fund = A + B = $106,000<BR>\n" );
document.write( "====================================== </SPAN>\n" );
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