document.write( "Question 33352: How do I solve this problem?\r
\n" ); document.write( "\n" ); document.write( "2x^2-3x+1=0
\n" ); document.write( "

Algebra.Com's Answer #19736 by sarah_adam(201)\"\" \"About 
You can put this solution on YOUR website!
2\"x%5E2\"-3x+1=0
\n" ); document.write( "2\"x%5E2\"-2x-x+1=0
\n" ); document.write( "2x(x-1)-1(x-1)=0
\n" ); document.write( "(2x-1)(x-1) = 0
\n" ); document.write( "(2x-1)=0 or (x-1) = 0
\n" ); document.write( "2x = 1 or x =1
\n" ); document.write( "x = 1/2 or x = 1
\n" ); document.write( "
\n" ); document.write( "
\n" );