document.write( "Question 269223: Gerry mixes different solutions with concentrations of 25%, 40%, and 50% to get 200 liters fo a 32% solution. Also, it takes twice the liters of the 40% solution to equal the same liters of the 25% , find how mnay liters of each kind he uses.\r
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document.write( "I have set up a table, but do not understand how the 50% factors in. Please help. Thank you! \n" );
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Algebra.Com's Answer #197358 by josmiceli(19441) You can put this solution on YOUR website! Let \n" ); document.write( "Let \n" ); document.write( "Let \n" ); document.write( "given: \n" ); document.write( "(1) \n" ); document.write( "(2) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "(3) \n" ); document.write( "Multiply both sides of (1) by \n" ); document.write( "and subtract from (3) \n" ); document.write( "(3) \n" ); document.write( "(1) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Going back to (1) \n" ); document.write( "(1) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "And, since \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "(1) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "120 liters of 25% solution are needed \n" ); document.write( "60 liters of 40% solution are needed \n" ); document.write( "20 liters of 50% solution are needed \n" ); document.write( "check: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |