document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=33348>Question 33348</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0072934824/algebrahomeworkh>algebra for college students</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> I need to solve this system of linear equations and I am having a hard time. Please help. \r<BR>\n" );
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document.write( "x-3y+2z =-11<BR>\n" );
document.write( "2x-4y+3z =-15<BR>\n" );
document.write( "3x-5y-4z =5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19734 by </B><A HREF=/tutors/aboutme.mpl?userid=sarah_adam><B>sarah_adam(201)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sarah_adam><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19734\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x-3y+2z =-11 --- eq 1<BR>\n" );
document.write( "2x-4y+3z =-15 --- eq 2<BR>\n" );
document.write( "3x-5y-4z =5  --- eq 3\r<BR>\n" );
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document.write( "from eq 1 we get x = 3y - 2z -11<BR>\n" );
document.write( "substituting the value of x in eq 2<BR>\n" );
document.write( "2(3y - 2z -11) - 4y +3z = -15<BR>\n" );
document.write( "6y - 4z -22 -4y +3z = -15<BR>\n" );
document.write( "2y - z = 22 - 15 = 7 <BR>\n" );
document.write( "2y - z = 7 ----eq 4<BR>\n" );
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document.write( "substitute value of x again in eq 3<BR>\n" );
document.write( "3(3y - 2z -11)-5y-4z = 5<BR>\n" );
document.write( "9y - 6z -33-5y-4z = 5<BR>\n" );
document.write( "4y-10z = 33 + 5 = 38<BR>\n" );
document.write( "4y-10z = 38 --- eq 5<BR>\n" );
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document.write( "2y - z = 7 ----eq 4<BR>\n" );
document.write( "4y-10z = 38 --- eq 5<BR>\n" );
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document.write( "multiply entire eq 4 with 2 <BR>\n" );
document.write( "4y - 2z = 14  --- eq 4  (after multipling the entire equation with 4)\r<BR>\n" );
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document.write( "subtracting eq 5 and eq 4\r<BR>\n" );
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document.write( "4y-10z = 38<BR>\n" );
document.write( "4y - 2z = 14<BR>\n" );
document.write( "(- )  (+ )   (-)      changing signs<BR>\n" );
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document.write( "  -8z = 24<BR>\n" );
document.write( "z = -(24/8)= -3\r<BR>\n" );
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document.write( "substituting the value of Z in eq 4<BR>\n" );
document.write( "2y - z = 7 <BR>\n" );
document.write( "2y -(-3)=7<BR>\n" );
document.write( "2y +3 = 7<BR>\n" );
document.write( "2y = 7-3 = 4<BR>\n" );
document.write( "y = 4/2 = 2\r<BR>\n" );
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document.write( "substitue the values of y and z in : x = 3y - 2z -11<BR>\n" );
document.write( "x = 3(2)-2(-3)-11<BR>\n" );
document.write( "x = 6 +6-11 = 12 -11 = 1\r<BR>\n" );
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document.write( "x = 1 ; y = 2 ; z = -3\r<BR>\n" );
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document.write( " </SPAN>\n" );
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