document.write( "Question 269240: It takes one hour longer to fly to St. Paul at 200 mi/h than it does to return at 250 mi/h. How far away is St. Paul? I think it involves the use of the distance formula d=rt but I'm not sure how to use it because this problem only gives me \"one hour longer\" as a time. \n" ); document.write( "
Algebra.Com's Answer #197321 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
It takes one hour longer to fly to St. Paul at 200 mi/h than it does to return at 250 mi/h.
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\n" ); document.write( "Slow leg:
\n" ); document.write( "rate = 200 mph ; time = x hrs. : distance = rt = 200x miles
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\n" ); document.write( "Fast leg:
\n" ); document.write( "rate = 250 mph ; time = x-1 hrs ; distance = rt = 250(x-1) miles
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\n" ); document.write( "Equation:
\n" ); document.write( "distance = distance
\n" ); document.write( "200x = 250(x-1)
\n" ); document.write( "200x = 250x - 250
\n" ); document.write( "-50x = -250
\n" ); document.write( "x = 5 hrs.
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\n" ); document.write( "Distance = 200x = 200*5 = 1000 miles
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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\n" ); document.write( "\n" ); document.write( "How far away is St. Paul? I think it involves the use of the distance formula d=rt but I'm not sure how to use it because this problem only gives me \"one hour longer\" as a time.
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