document.write( "Question 269156: When the digits of a two-digit number is 9 more than the original number, and the sum of the digits of the original number is 11. What is the original number? \n" ); document.write( "
Algebra.Com's Answer #197298 by ankor@dixie-net.com(22740)\"\" \"About 
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I think this problem should read:
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\n" ); document.write( "\"When the digits of a two-digit number are reversed, the number is 9 more than the original number, and the sum of the digits of the original number is 11.
\n" ); document.write( " What is the original number?\"
\n" ); document.write( ":
\n" ); document.write( "Let x = the 10's digit
\n" ); document.write( "Let y = the units
\n" ); document.write( "the
\n" ); document.write( "10x + y = \"the original two digit number
\n" ); document.write( ":
\n" ); document.write( "\"When the digits of a two-digit number are reversed, the number is 9 more than the original number,\"
\n" ); document.write( "10y + x = 10x + y + 9
\n" ); document.write( "10y - y = 10x - x + 9
\n" ); document.write( "9y = 9x + 9
\n" ); document.write( "Simplify divide by 9
\n" ); document.write( "y = x + 1
\n" ); document.write( ":
\n" ); document.write( "\"the sum of the digits of the original number is 11.
\n" ); document.write( "x + y = 11
\n" ); document.write( "Replace y with (x+1)
\n" ); document.write( "x + x + 1 = 11
\n" ); document.write( "2x = 11-1
\n" ); document.write( "x = 5
\n" ); document.write( "then
\n" ); document.write( "y = 5 + 1 = 6
\n" ); document.write( ":
\n" ); document.write( "56 is the original number
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\n" ); document.write( ":
\n" ); document.write( "Check solution in the statement:
\n" ); document.write( "\"the digits of a two-digit number are reversed, the number is 9 more than the original number,\"
\n" ); document.write( "65 = 56 + 9\r
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