document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=269189>Question 269189</A>: <I><SPAN STYLE=\"word-break: break-all;\"> e^-t/4.6=1.73^2.7t      The answer is t=0, how do you get this? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #197295 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=197295\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if t=0, then the exponents are zero and (by definition) both sides equal one\r<BR>\n" );
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document.write( "this is a \"default\" solution ___ changing any or all other values in the equation does not change the solution\r<BR>\n" );
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document.write( "___ alternatively ___\r<BR>\n" );
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document.write( "taking the natural log ___ -t / 4.6 = ln(1.73) * 2.7t\r<BR>\n" );
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document.write( "multiplying by 4.6 ___ -t = ln(1.73) * 12.42t\r<BR>\n" );
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document.write( "adding t-ln(1.73) ___ -ln(1.73) = 13.42t\r<BR>\n" );
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document.write( "dividing by 13.42 ___ -ln(1.73) / 13.42 = t\r<BR>\n" );
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document.write( "t = -.0408 (approx) </SPAN>\n" );
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