document.write( "Question 269193: Use the discriminant to determine how many real-number solutions the equation has. s2 - 5s + 6 = 0 \n" ); document.write( "

Algebra.Com's Answer #197290 by josmiceli(19441) $\"\"$ $\"About$

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The discriminant is $\"b%5E2+-+4ac\"$ in the formula
\n" ); document.write( " $\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$
\n" ); document.write( "As long as $\"b%5E2+-+4ac+\"$ is (+), then the roots are real
\n" ); document.write( "You are given $\"s%5E2+-+5s+%2B+6+=+0\"$
\n" ); document.write( " $\"b%5E2+-+4ac+=+%28-5%29%5E2+-+4%2A1%2A6\"$
\n" ); document.write( " $\"b%5E2+-+4ac+=+25+-+24\"$
\n" ); document.write( " $\"b%5E2+-+4ac+=+1\"$
\n" ); document.write( "There are 2 real roots, If the discrinant were $\"0\"$ ,
\n" ); document.write( "there would be 1 real root\r
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