document.write( "Question 269118: 1.The sum of three consecutive odd integers is -3. What are the integers.
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document.write( "2. The perimeter of a rectangle is 68 meters. The width is one-hald meter less than one half of the length. What is the area of the rectangle.
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Algebra.Com's Answer #197269 by mananth(16949) You can put this solution on YOUR website! The sum of three consecutive odd integers is -3. What are the integers. \n" ); document.write( "2. The perimeter of a rectangle is 68 meters. The width is one-hald meter less than one half of the length. What is the area of the rectangle.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "let the integer x\r \n" ); document.write( "\n" ); document.write( "next two odd integer will be x-2 and x-4\r \n" ); document.write( "\n" ); document.write( "x+x-2 +x-4=-3\r \n" ); document.write( "\n" ); document.write( "3x-6=-3 \n" ); document.write( "3x=3 \n" ); document.write( "x=1\r \n" ); document.write( "\n" ); document.write( "2. The perimeter of a rectangle is 68 meters. The width is one-half meter less than one half of the length. What is the area of the rectangle.\r \n" ); document.write( "\n" ); document.write( "let the length be x\r \n" ); document.write( "\n" ); document.write( "width = x/2 -1/2\r \n" ); document.write( "\n" ); document.write( "2x+ 2(x/2-1/2) =68\r \n" ); document.write( "\n" ); document.write( "2x+x-1=68 \n" ); document.write( "3x=69 \n" ); document.write( "x=23\r \n" ); document.write( "\n" ); document.write( "y=11\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |