document.write( "Question 269127: A rectangular box with no top has height 4 feet. The length of the base is three
\n" ); document.write( "times the width, and the volume is 300 cubic feet. Find the amount of cardboard
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Algebra.Com's Answer #197264 by Earlsdon(6294)\"\" \"About 
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The volume of the open-top box (V) is given as 300 sq.ft.
\n" ); document.write( "For a rectangular prism (a box), the volume is given by:
\n" ); document.write( "\"V+=+L%2AW%2Ah\" and, in this problem, V = 300 sq.ft., h = 4 ft., W = W and L = 3W, so...
\n" ); document.write( "\"%283W%29%2A%28W%29%2A4+=+300\" Simplify.
\n" ); document.write( "\"12W%5E2+=+300\" Divide by 12.
\n" ); document.write( "\"W%5E2+=+25\" and...
\n" ); document.write( "\"W+=+5\"ft. (Discard the negative solution from the square root).
\n" ); document.write( "\"L+=+3W\"
\n" ); document.write( "\"L+=+15\"ft.
\n" ); document.write( "So, to construct an open-top box with the foregoing dimensions, you would need to start with a rectangular sheet of cardboard with a length (l) of L+2h and a width (w) of W+2h, so...
\n" ); document.write( "\"l+=+15%2B2%284%29\"
\n" ); document.write( "\"l+=+23\" and...
\n" ); document.write( "\"w+=+W%2B2%284%29\"
\n" ); document.write( "\"w+=+5%2B8\"
\n" ); document.write( "\"w+=+13\"
\n" ); document.write( "The initial sheet of cardboard has to be 23ft. by 13ft, from which you would cut the four corners measuring 4ft. by 4ft.
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