document.write( "Question 269123: Hoping someone will help me with a few more. I need to see the steps:)\r
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document.write( "Verify:
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document.write( "a)sinx(sinx+cscxcos^2x)=1
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document.write( "b)tanx((cotx/cosx)-sinx)=cosx
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document.write( "c)(1+cosx)(1-cosx)=sin^2x \n" );
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Algebra.Com's Answer #197255 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Verify: \n" ); document.write( "a)sinx(sinx+cscxcos^2x)=1 \n" ); document.write( "--- \n" ); document.write( "sin^2(x) + (1)cos^2(x) = 1 \n" ); document.write( "--- \n" ); document.write( "sin^2(x) + cos^2(x) is always 1, so you get: \n" ); document.write( "1 = 1 \n" ); document.write( "-----------------------\r \n" ); document.write( "\n" ); document.write( "b)tanx((cotx/cosx)-sinx)=cosx \n" ); document.write( "--- \n" ); document.write( "tan(x)[(1/tan(x))/cos(x) - sin(x)) = cos(x) \n" ); document.write( "--- \n" ); document.write( "(1/cos(x) - sin(x) = cos(x) \n" ); document.write( "Multiply thru by cos(x) to get: \n" ); document.write( "1 - cos(x)sin(x) = cos^2(x) \n" ); document.write( "This is not an identity. \n" ); document.write( "The left side of the original eq. does not equal the right side. \n" ); document.write( "-------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "c)(1+cosx)(1-cosx)=sin^2x \n" ); document.write( "----- \n" ); document.write( "1-cos^2(x) = sin^2(x) \n" ); document.write( "sin^2(x) = sin^2(x) \n" ); document.write( "============================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |