document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=269131>Question 269131</A>: <I><SPAN STYLE=\"word-break: break-all;\"> There is a rectangle with the width = L and the length = L+60. If the perimeter is 200cm, write an equation in terms of L? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #197252 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=197252\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There is a rectangle with the width = L and the length = L+60. If the perimeter is 200cm, write an equation in terms of L?<BR>\n" );
document.write( "------------------------<BR>\n" );
document.write( "Perimeter = 2(length + width)<BR>\n" );
document.write( "200 = 2(L+60 + L)<BR>\n" );
document.write( "100 = 2L + 60<BR>\n" );
document.write( "2L = 40<BR>\n" );
document.write( "L = 20<BR>\n" );
document.write( "----------------------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );