document.write( "Question 269102: A sum of Rs.6240 is paid off in 30 instalments such that each instalment is Rs. 10 more than the proceeding instalment. the value of the 1st instalment is.
\n" ); document.write( "(A)Rs=36 (B)Rs=30 (C)Rs=60 (D) none of these. \n" ); document.write( "

Algebra.Com's Answer #197239 by checkley77(12844) $\"\"$ $\"About$

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Break this problem up into different pieces & solve.
\n" ); document.write( "6240=30x+29/2(10+290)
\n" ); document.write( "1st. payment=x
\n" ); document.write( "2nd. payment=x+10
\n" ); document.write( "3rd. payment=x+20
\n" ); document.write( "****
\n" ); document.write( "****
\n" ); document.write( "30th paynebt=x+290
\n" ); document.write( "Payment sum=30x+29/2(10+290)
\n" ); document.write( "The 30x is the total of the base payments.
\n" ); document.write( "The 29/2(10+290) is the sum of the increasing additional payments for the last 29 payments.
\n" ); document.write( "6240=30x+14.5*300
\n" ); document.write( "6240=30x+4350
\n" ); document.write( "30x=6240-4350
\n" ); document.write( "30x=1890
\n" ); document.write( "x=1890/30
\n" ); document.write( "x=$63 is the amount of the first payment.
\n" ); document.write( "Proof:
\n" ); document.write( "30(63+63+290)/2
\n" ); document.write( "30*416/2
\n" ); document.write( "15*416=6,240 \n" ); document.write( "

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