document.write( "Question 269106: 15 pounds of anchovies are needed for 7 pizzerias for 2 days. How many pounds are needed for 4 pizzerias for 7 days? \n" ); document.write( "

Algebra.Com's Answer #197231 by josmiceli(19441) $\"\"$ $\"About$

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One way to look at it is that anchovies for 4 pizzarias for 7 days
\n" ); document.write( "would be the same as 7 pizzarias for 4 days.
\n" ); document.write( "That would be twice as much anchovies as 7 pizzarias for 2 days
\n" ); document.write( "and that would be $\"2%2A15+=+30\"$ lbs
\n" ); document.write( "Another way is:
\n" ); document.write( "15 a for 7 p for 2 days =
\n" ); document.write( "(15/2) a for 7 p for 1 day =
\n" ); document.write( "(15/14) a for 1 p for 1 day =
\n" ); document.write( "(15/14)x(7) a for 1 p for 7 days =
\n" ); document.write( "(15/14)x(7)x(4) a for 4 p for 7 d
\n" ); document.write( " $\"%2815%2F14%29%2A7+%2A4+=+30\"$
\n" ); document.write( "30 pounds are needed for 4 pizzarias for 7 days\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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