document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=269031>Question 269031</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 3 in more than twice the width. the area is 189^2  what is the length of the triangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #197225 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=197225\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 3 in more than twice the width. the area is 189 what is the length of the rectangle?\r<BR>\n" );
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document.write( "let the width be x\r<BR>\n" );
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document.write( "length = 2x+3\r<BR>\n" );
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document.write( "x(2x+3) = 189<BR>\n" );
document.write( "2x^2+3x-189=0\r<BR>\n" );
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document.write( "2x^2+-18x+21x-189=0\r<BR>\n" );
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document.write( "2x(x-9)+21(x-9)=0<BR>\n" );
document.write( "(x-9)(2x+21)=0\r<BR>\n" );
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document.write( "x=9  or x= -21/2\r<BR>\n" );
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document.write( "x=9 which is the width since the width can't be negative\r<BR>\n" );
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