document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=269051>Question 269051</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi I need help in solving this equation:\r<BR>\n" );
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document.write( "Divide:\r<BR>\n" );
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document.write( "(20b^3+12b^2+20b+34)/(4b+4)\r<BR>\n" );
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document.write( "thanks, </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #197184 by </B><A HREF=/tutors/aboutme.mpl?userid=persian52><B>persian52(161)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=persian52><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=persian52><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=197184\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (20b^(3)+12b^(2)+20b+34)/(4b+4)\r<BR>\n" );
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document.write( "Factor out the GCF of 2 from each term in the polynomial.<BR>\n" );
document.write( "(2(10b^(3))+2(6b^(2))+2(10b)+2(17))/(4b+4)\r<BR>\n" );
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document.write( "Factor out the GCF of 2 from 20b^(3)+12b^(2)+20b+34.<BR>\n" );
document.write( "(2(10b^(3)+6b^(2)+10b+17))/(4b+4)\r<BR>\n" );
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document.write( "Factor out the GCF of 4 from each term in the polynomial.<BR>\n" );
document.write( "(2(10b^(3)+6b^(2)+10b+17))/(4(b)+4(1))\r<BR>\n" );
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document.write( "Factor out the GCF of 4 from 4b+4.<BR>\n" );
document.write( "(2(10b^(3)+6b^(2)+10b+17))/(4(b+1))\r<BR>\n" );
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document.write( "Reduce the expression (2(10b^(3)+6b^(2)+10b+17))/(4(b+1)) by removing a factor of 2 from the numerator and denominator.<BR>\n" );
document.write( "Answer: (10b^(3)+6b^(2)+10b+17)/(2(b+1)) </SPAN>\n" );
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