document.write( "Question 269048: I do not even know were to start for this problem because i only know how to solve problems of two equations with two variables. I would like to know how to solve it as well as a answer for x,y, and z\r
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\n" ); document.write( "\n" ); document.write( "x + y + z = 1
\n" ); document.write( "5x + 4y + 4z = 6
\n" ); document.write( "4x + 5y + 6z = −3 \n" ); document.write( "
Algebra.Com's Answer #197166 by Alan3354(69443)\"\" \"About 
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x + y + z = 1
\n" ); document.write( "5x + 4y + 4z = 6
\n" ); document.write( "4x + 5y + 6z = −3
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\n" ); document.write( "One method is elimination. Eliminate one of the variables, make it 2 eqns with 2 variables.
\n" ); document.write( "Pick a variable to eliminate. Makes no difference, any one. I'll do z.
\n" ); document.write( "Multiply eqn 1 by 4 and subtract it from eqn 2.
\n" ); document.write( "5x + 4y + 4z = 6
\n" ); document.write( "4x + 4y + 4z = 4
\n" ); document.write( "------------------- subtract
\n" ); document.write( "x = 2
\n" ); document.write( "That's even better, usually it's not that easy.
\n" ); document.write( "Sub 2 for x in 2 of the eqns, I'll do 1 and 2
\n" ); document.write( "y + z = -1
\n" ); document.write( "4y+4z = -4
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\n" ); document.write( "Now there's a problem, the 2nd eqn is -4 times the first.
\n" ); document.write( "--> dependent, no unique solution.
\n" ); document.write( "An infinite # of solutions.\r
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