document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=269041>Question 269041</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you find the domain of f(x)=(x^2)ln(15-2(x^2)) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #197161 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=197161\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do you find the domain of f(x)=(x^2)ln(15-2(x^2))<BR>\n" );
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document.write( "You cannot find the ln of a negative number or zero,<BR>\n" );
document.write( "So, 15-2x^2 must be positive<BR>\n" );
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document.write( "Solve 15-2x^2 > 0<BR>\n" );
document.write( "2x^2 < 15<BR>\n" );
document.write( "x^2 < 15/2<BR>\n" );
document.write( "-(15/2)sqrt(2) < x < (15/2)sqrt(2)<BR>\n" );
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document.write( "Domain: All Real Numbers x where -(15/2)sqrt(2)< x < (15/2)sqrt(2)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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