document.write( "Question 268616: Going into the final exam, which will count 2/3's of the final grade, Mike has test scores of 86, 80, 84, 90. What score does Mike need on the final in order to earn a B, which requires an average score of 80? What score would he need for an A?\r
\n" ); document.write( "\n" ); document.write( "Do I simply find the average of the test scores and assume it's 1/3 of his final grade?\r
\n" ); document.write( "\n" ); document.write( "Does it look like this:
\n" ); document.write( "(85)1/3+ x2/3= 80\r
\n" ); document.write( "\n" ); document.write( "and to find his grade for an \"A\":
\n" ); document.write( "85(1/3)+ x2/3+90\r
\n" ); document.write( "\n" ); document.write( "Thank you! \n" ); document.write( "
Algebra.Com's Answer #197156 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Going into the final exam, which will count 2/3's of the final grade,
\n" ); document.write( "Mike has test scores of 86, 80, 84, 90.
\n" ); document.write( "What score does Mike need on the final in order to earn a B, which requires an average score of 80?:
\n" ); document.write( ":
\n" ); document.write( "I think you can do it that way, this is the way I would do it:\r
\n" ); document.write( "\n" ); document.write( "Average the 4 grades that represent 1/3
\n" ); document.write( "\"%2886%2B80%2B84%2B90%29%2F4\" = 85
\n" ); document.write( ":
\n" ); document.write( "x = 2/3 the final grade or twice as much as first 4 grades
\n" ); document.write( ":
\n" ); document.write( "\"%2885+%2B+2x%29%2F3\" = 80
\n" ); document.write( "multiply by 3
\n" ); document.write( "85 + 2x = 3(80)
\n" ); document.write( "2x = 240 - 85
\n" ); document.write( "2x = 155
\n" ); document.write( "x = \"155%2F2\"
\n" ); document.write( "x = 77.5 to get 80% for a B
\n" ); document.write( ":
\n" ); document.write( "Your way would get the same answer.
\n" ); document.write( ":
\n" ); document.write( "What score would he need for an A? \n" ); document.write( "
\n" );