document.write( "Question 268999: 1. -2/y^2 - 9 + 4y/(y - 3)^2 + 6/3 - y
\n" );
document.write( "2. x^2/3x^2 - 5x - 2 - 2x/3x + 1 divived by 1/x - 2 \n" );
document.write( "
Algebra.Com's Answer #197144 by drk(1908)![]() ![]() ![]() You can put this solution on YOUR website! 1. -2/(y^2 - 9) + 4y/(y - 3)^2 + 6/(3 - y) \n" ); document.write( "factor the denominators to get \n" ); document.write( " \n" ); document.write( "change the last sign to minus by the negative 1 rule and we get \n" ); document.write( " \n" ); document.write( "our common denominator is (y-3)^2(y+3). We change our numerators as \n" ); document.write( " \n" ); document.write( "simplify the numerator as \n" ); document.write( " \n" ); document.write( "----- \n" ); document.write( "2. \n" ); document.write( "factor the first fractions as \n" ); document.write( " \n" ); document.write( "add the numerator fractions to get \n" ); document.write( " \n" ); document.write( "simplifying we get \n" ); document.write( " \n" ); document.write( "multiply both fractions by x-2 we get \n" ); document.write( " \n" ); document.write( "if you want to factor the numerator, we get \n" ); document.write( " |