document.write( "Question 268982: paul left springfield traveling north at an average speed of 64 miles per hour. tim left springfield traveling south at an avergae spped of 58 miles per hour. how long would it take after paul left for them to be 982 miles apart? how many hours would it be after paul left? \n" ); document.write( "
Algebra.Com's Answer #197127 by drk(1908)\"\" \"About 
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This is an RTD problem. Here is a table based on the given information
\n" ); document.write( "direction . . . . . . . . .rate . . . . . . . . .. time . . . . . . . . .. distance
\n" ); document.write( "Paul (N) . . . . . . . . . . 64. . . . . . . . . . . t. . . . . . . . . . . . . 64t
\n" ); document.write( "Tim (S) . . . . . . . . . . .58. . . . . . . . . . .t - h. . . . . . . . . . .58t - 58h
\n" ); document.write( "distances . . . . . . . . . . . . . . . . . . . . .2t. . . . . . . . . . . . 982
\n" ); document.write( "We don't know when Tim left. We want them 982 miles apart but the distance are increasing, so we add to get
\n" ); document.write( "64t + 58t - 58h = 982
\n" ); document.write( "or
\n" ); document.write( "122t - 58h = 982
\n" ); document.write( "solving for t, we get
\n" ); document.write( "t = (982+58h)/122
\n" ); document.write( "If h = 2, then t = 9
\n" ); document.write( "It would 9 hours after PAul left to be 982 miles apart.
\n" ); document.write( "It would be 7 hours after Tim left. \n" ); document.write( "
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