document.write( "Question 268974: bOB HAS 60 COINS CONSISTING OF QUARTERS AND DIMES.tHE COINS COMBINED VALUE IS $9.45. FIND OUT HOW ARE QUATERS AND MANY DIMES. \n" ); document.write( "
Algebra.Com's Answer #197121 by JBarnum(2146)\"\" \"About 
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\"Q%2BD=60\" where 60=total coins and D is the number of dimes and Q is the number of quarters. the value of C=9.45 so the value of Q+ the value of D= the value of C. to make this a bit easier to see the value of quarters =Q(.25) , the value of dimes =D(.10) , and the value of the total coins =9.45
\n" ); document.write( "this equation looks like: \"Q%28.25%29%2BD%28.10%29=9.45\"
\n" ); document.write( "now you have 2 equations and now u can use the substitution method to find your answers.
\n" ); document.write( "_______________
\n" ); document.write( "Equations:
\n" ); document.write( "\"Q%28.25%29%2BD%28.10%29=9.45\"
\n" ); document.write( "\"Q%2BD=60\" so \"D=60-Q\"
\n" ); document.write( "_____________________
\n" ); document.write( "\"Q%28.25%29%2B%2860-Q%29%28.10%29=9.45\"
\n" ); document.write( "\".25Q%2B6-.10Q=9.45\"
\n" ); document.write( "\".25Q%2B6-6-.10Q=9.45-6\"
\n" ); document.write( "\".25Q-.10Q=3.45\"
\n" ); document.write( "\".15Q%2F.15=3.45%2F.15\"
\n" ); document.write( "\"Q=23\" 23 Quarters
\n" ); document.write( "____________________
\n" ); document.write( "\"D=60-Q\"
\n" ); document.write( "\"D=60-23\"
\n" ); document.write( "\"D=37\" 37 Dimes
\n" ); document.write( "_____________________
\n" ); document.write( "Check answer
\n" ); document.write( "\"Q%28.25%29%2BD%28.10%29=9.45\"
\n" ); document.write( "\"23%28.25%29%2B37%28.10%29=9.45\"
\n" ); document.write( "\"5.75%2B3.70=9.45\"
\n" ); document.write( "\"9.45=9.45\"
\n" ); document.write( "correct
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