document.write( "Question 268499: Solve algebraically: ln3+ln(x-6)=ln(x+5) \n" ); document.write( "

Algebra.Com's Answer #197105 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Solve algebraically: ln3+ln(x-6)=ln(x+5)
\n" ); document.write( "Adding logs means mult so we can write it:
\n" ); document.write( "ln(3(x-6)) = ln(x+5)
\n" ); document.write( ":
\n" ); document.write( "ln(3x - 18) = ln(x + 5)
\n" ); document.write( "therefore
\n" ); document.write( "3x - 18 = x + 5
\n" ); document.write( ":
\n" ); document.write( "3x - x = 5 + 18
\n" ); document.write( ":
\n" ); document.write( "2x = 23
\n" ); document.write( ":
\n" ); document.write( "x = 11.5
\n" ); document.write( ";
\n" ); document.write( ":
\n" ); document.write( "Check on a calc, the original equation
\n" ); document.write( "enter: ln(3) + ln(11.5-6) results: 2.0833
\n" ); document.write( "enter: ln(11.5+5) results: 2.0833; equality confirms our solution of x = 11.5 \n" ); document.write( "

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