document.write( "Question 268974: bOB HAS 60 COINS CONSISTING OF QUARTERS AND DIMES.tHE COINS COMBINED VALUE IS $9.45. FIND OUT HOW ARE QUATERS AND MANY DIMES. \n" ); document.write( "

Algebra.Com's Answer #197104 by drk(1908) $\"\"$ $\"About$

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we need two equations
\n" ); document.write( "(i) $\"D+%2B+Q+=+60\"$
\n" ); document.write( "(ii) $\"10D+%2B+25Q+=+945\"$
\n" ); document.write( "step 1 - multiply (i) by -10 to get
\n" ); document.write( "(iii) $\"-10D+-+10Q+=+-600\"$
\n" ); document.write( "step 2 - add (ii) and (iii) to get
\n" ); document.write( "(iv) $\"15Q+=+345\"$
\n" ); document.write( "step 3 - divide by 15 to get
\n" ); document.write( "(v) $\"Q+=+23\"$
\n" ); document.write( "Since Q =23, we know that
\n" ); document.write( "(vi) $\"+D+=+37\"$ \n" ); document.write( "

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