document.write( "Question 33306: A plane flies 720 miles against a steady 30-mi/h headwind and then returns to the same point with the wind. If the entire trip takes 10 hours, what is the planes's speed in still air. \n" ); document.write( "
Algebra.Com's Answer #19710 by Paul(988)![]() ![]() ![]() You can put this solution on YOUR website! Plane total distance = 720 miles: \n" ); document.write( "With the wind the plane speed is: x+30 \n" ); document.write( "Against the wind: x-30 \n" ); document.write( "Total time of them both = 10h \n" ); document.write( "equation: \n" ); document.write( " \n" ); document.write( "720[(x-30)+(x+30)]=10[(x-30)(x+30)] \n" ); document.write( "720(2x)=10(x^2-900) \n" ); document.write( "10x^2-9000-1440x=0 \n" ); document.write( "x^2-144x-900=0 \n" ); document.write( " \n" ); document.write( "Use quadratic formula: \n" ); document.write( "in \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Add: \n" ); document.write( " \n" ); document.write( "x=150\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hence the speed of the plane in still air is 150mi/h. \n" ); document.write( "Paul.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |