document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=268961>Question 268961</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The hypotenuse of a right triangle is 14. One of the triangles side lengths is 7. Find length of the remaining side. \r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #197061 by </B><A HREF=/tutors/aboutme.mpl?userid=drk><B>drk(1908)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=197061\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are two ways to solve this based on your knowledge level:<BR>\n" );
document.write( "(1) a^2 + b^2 = c^2<BR>\n" );
document.write( "7^2 + b^2 = 14^2<BR>\n" );
document.write( "49 + b^2 = 196<BR>\n" );
document.write( "b^2 = 147<BR>\n" );
document.write( "b = 12.12<BR>\n" );
document.write( "----<BR>\n" );
document.write( "(2) one side is 1/2 the hypotenuse. the other side is that side x sqrt(3). IN our case we get 7*sqrt(3) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );