document.write( "Question 268965: $\"3log%285%2Cx%29+-+log%285%2C4%29+=+log%285%2C16%29\"$ \n" ); document.write( "

Algebra.Com's Answer #197058 by drk(1908) $\"\"$ $\"About$

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First we use the power rule to get
\n" ); document.write( " $\"log%285%2Cx%5E3%29+-+log%285%2C4%29+=+log%285%2C16%29\"$
\n" ); document.write( "next, when we subtract logs, we divide the information to get
\n" ); document.write( " $\"log%285%2Cx%5E3%2F4%29+=+log%285%2C16%29\"$
\n" ); document.write( "third, eliminate the logs to get
\n" ); document.write( " $\"x%5E3%2F4+=+16\"$
\n" ); document.write( "multiply by 4 to get
\n" ); document.write( " $\"x%5E3+=+64\"$
\n" ); document.write( "taking a cube root we get
\n" ); document.write( " $\"x+=+4\"$ \n" ); document.write( "

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