document.write( "Question 268923: A woman is 20 years more than the age of her daughter: x + 20
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document.write( "Her daughter will be represented by x: x
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document.write( "In 11 years she will be 3 years less than twice her daughters age: 11(2x - 3)
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document.write( "How old is each now?\r
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document.write( "So is this how I set it up:\r
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document.write( " x + 20 = 11(2x - 3)\r
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document.write( "Please help me. \n" );
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Algebra.Com's Answer #197044 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! A woman is 20 years more than the age of her daughter: x + 20 \n" ); document.write( "Her daughter will be represented by x: x \n" ); document.write( "In 11 years she will be 3 years less than twice her daughters age: 11(2x - 3) \n" ); document.write( "How old is each now? \n" ); document.write( "So is this how I set it up: \n" ); document.write( "x + 20 = 11(2x - 3) \n" ); document.write( "------------------ \n" ); document.write( "W = D + 20 \n" ); document.write( "W + 11 = 2(D+11) - 3 = 2D + 19 \n" ); document.write( "--------------- \n" ); document.write( "Sub for W \n" ); document.write( "D+20 + 11 = 2D+19 \n" ); document.write( "D+31 = 2D+19 \n" ); document.write( "D = 12 \n" ); document.write( "W = 32 \n" ); document.write( "------- \n" ); document.write( "In 11 yrs, D=23, W=43 \n" ); document.write( "2*23-3 = 43 so it's good \n" ); document.write( " \n" ); document.write( " |