document.write( "Question 268929: If I know the perimeter of a rectangle is 34 and the area is 60 how do I find the sides? \n" ); document.write( "
Algebra.Com's Answer #197037 by CharlesG2(834)\"\" \"About 
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If I know the perimeter of a rectangle is 34 and the area is 60 how do I find the sides?
\n" ); document.write( "perimeter is 2 * (length + width) or 2L + 2W
\n" ); document.write( "area is length * width or L*W\r
\n" ); document.write( "\n" ); document.write( "2L + 2W = 34 (divide both sides by 2)
\n" ); document.write( "L + W = 17 (you can solve this for L to have L in terms of W, or solve for W to have W in terms of L)\r
\n" ); document.write( "\n" ); document.write( "L * W = 60 (so now we know the sum is 17 and the product is 60)\r
\n" ); document.write( "\n" ); document.write( "should subsitute in to the product equation (L*W=60) either L in terms of W and solve for W then solve for L or W in terms of L and solve for L then solve for W\r
\n" ); document.write( "\n" ); document.write( "L * W = 60
\n" ); document.write( "L * (17 - L) = 60 (substituted in)
\n" ); document.write( "17L - L^2 = 60 (rearrange)
\n" ); document.write( "-L^2 + 17L - 60 = 0 (divide both sides by -1)
\n" ); document.write( "L^2 - 17L + 60 = 0 (solve for L)
\n" ); document.write( "(L-12)(L-5) = 0 (foil: L^2 - 5L - 12L + 60)
\n" ); document.write( "L=5 or L=12
\n" ); document.write( "since L+W=17 then W=12 or W=5 \r
\n" ); document.write( "\n" ); document.write( "L*W = 12 * 5 = 60
\n" ); document.write( "2 * (L+W) = 2 * 17 = 34\r
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