document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=268908>Question 268908</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 36 inches. the length exceeds the width by 4 inches. what is the length and width\r<BR>\n" );
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document.write( "length =<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #197024 by </B><A HREF=/tutors/aboutme.mpl?userid=vksarvepalli><B>vksarvepalli(154)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vksarvepalli><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=vksarvepalli><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=197024\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> perimeter of a rectangle with length l and width w is given by 2(l+w)\r<BR>\n" );
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document.write( "now given 2(l+w)=36  -------------- 1\r<BR>\n" );
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document.write( "and l=w+4        ------------------ 2\r<BR>\n" );
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document.write( "so from eq.1  l+w=18  \r<BR>\n" );
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document.write( "and substituting the value of l from eq.2 <BR>\n" );
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document.write( " we get  w+4+w=18\r<BR>\n" );
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document.write( " => 2w+4=18<BR>\n" );
document.write( " => 2w=14<BR>\n" );
document.write( " => w=7\r<BR>\n" );
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document.write( "so    length=11<BR>\n" );
document.write( "   <BR>\n" );
document.write( "      width=7 </SPAN>\n" );
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