document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=268790>Question 268790</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much 3.5% milk and 1.0% milk must be mixed to produce 220 gallons of 2.0% milk? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #196983 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=196983\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3.5%=.035 TIMES SOME NUMBER OF GALLONS PLUS 1%=.01 TIMES THE REST OF THE GALLONS (220-X) RESULTS IN THE 2% OR .O2 TIMES THE ENTIRE 220 GALLONS. <BR>\n" );
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document.write( ".035x+.01(220-x)=.02*220<BR>\n" );
document.write( ".035x+2.2-.01x=4.4 <BR>\n" );
document.write( ".025x=4.4-2.2 (.035x-.010x=.025x)<BR>\n" );
document.write( ".025x=2.2<BR>\n" );
document.write( "x=2.2/.025<BR>\n" );
document.write( "x=88 gallons of 3.5% milk is used.<BR>\n" );
document.write( "220-88=132 gallons of 1% is used.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( ".035*88+.01*132=.02*220<BR>\n" );
document.write( "3.08+1.32=4.4<BR>\n" );
document.write( "4.4=4.4 </SPAN>\n" );
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