document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=268272>Question 268272</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2x+1=x-5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #196946 by </B><A HREF=/tutors/aboutme.mpl?userid=persian52><B>persian52(161)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=persian52><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=persian52><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=196946\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x+1=x-5\r<BR>\n" );
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document.write( "Since x contains the variable to solve for, move it to the left-hand side of the equation by subtracting x from both sides.<BR>\n" );
document.write( "2x+1-x=-5\r<BR>\n" );
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document.write( "Since 2x and -x are like terms, add -x to 2x to get x.<BR>\n" );
document.write( "x+1=-5\r<BR>\n" );
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document.write( "Since 1 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 1 from both sides.<BR>\n" );
document.write( "x=-1-5\r<BR>\n" );
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document.write( "Subtract 5 from -1 to get -6.<BR>\n" );
document.write( "x=-6 </SPAN>\n" );
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