document.write( "Question 268597: The ambulance got a flat tire, so Action Man had to take Ed to the hospital. Action Man ran 22 mph, and Ed's dog followed behind, running 11 mph. If the dog took 7.5 minutes longer than Action Man to get there, how far away was the hospital? \n" ); document.write( "
Algebra.Com's Answer #196928 by ankor@dixie-net.com(22740)\"\" \"About 
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Action Man ran 22 mph, and Ed's dog followed behind, running 11 mph. If the dog took 7.5 minutes longer than Action Man to get there, how far away was the hospital?
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\n" ); document.write( "Dog and man ran the same dist. write a dist equation:
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\n" ); document.write( "Change 7.5 min to 7.5/60 = .125 hrs
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\n" ); document.write( "Let t = Man's running time,
\n" ); document.write( "then
\n" ); document.write( "(t+.125) = dog's running time
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\n" ); document.write( "22t = 11(t+.125)
\n" ); document.write( "22t = 11t + 1.375
\n" ); document.write( "22t - 11t = 1.375
\n" ); document.write( "11t = 1.375
\n" ); document.write( "t = \"1.375%2F11\"
\n" ); document.write( "t = .125 hrs
\n" ); document.write( "Dist = 22 * .125 = 2.75 mi to hospital
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