document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=268729>Question 268729</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what strategies can you use to solve a linear equation such as 500=242+5x  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #196922 by </B><A HREF=/tutors/aboutme.mpl?userid=persian52><B>persian52(161)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=persian52><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=persian52><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=196922\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 500=242+5x\r<BR>\n" );
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document.write( "Since x is on the right-hand side of the equation, switch the sides so it is on the left-hand side of the equation.<BR>\n" );
document.write( "242+5x=500\r<BR>\n" );
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document.write( "Since 242 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 242 from both sides.<BR>\n" );
document.write( "5x=-242+500\r<BR>\n" );
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document.write( "Add 500 to -242 to get 258.<BR>\n" );
document.write( "5x=258\r<BR>\n" );
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document.write( "Divide each term in the equation by 5.<BR>\n" );
document.write( "(5x)/(5)=(258)/(5)\r<BR>\n" );
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document.write( "Simplify the left-hand side of the equation by canceling the common terms.<BR>\n" );
document.write( "x=(258)/(5) </SPAN>\n" );
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