document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=268621>Question 268621</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An air rescue plane averages 300 miles per hour in still air.  It carries enough fuel for 5 hours of flying time.  If, upon takeoff it encounters a head wind of 30 mi/hr and the wind remains constant, how far can the plane fly and then return safely?\r<BR>\n" );
document.write( "\n" );
document.write( "Is the rate simply 300-30?  How do I find the distance traveled? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #196921 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=196921\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> An air rescue plane averages 300 miles per hour in still air. It carries enough fuel for 5 hours of flying time. If, upon takeoff it encounters a head wind of 30 mi/hr and the wind remains constant, how far can the plane fly and then return safely? <BR>\n" );
document.write( "Is the rate simply 300-30? How do I find the distance traveled?\r<BR>\n" );
document.write( "\n" );
document.write( "The time the plane can stay in the air is 5 hours. As you determined, the speed that the plane can fly against the wind is 300-30. But on a round trip the plane will fly back with a speed of 300+30. \r<BR>\n" );
document.write( "\n" );
document.write( "Let t be the time taken for the trip against the wind. Then the part of the trip with the wind will be 5-t since the whole trip will take 5 hours. Let's say the distance for each leg of the trip is d.  Then we have:\r<BR>\n" );
document.write( "\n" );
document.write( "1.) d = rate*time = (300-30)*t  (against the wind)<BR>\n" );
document.write( "2.) d = rate*time = (300+30)*(5-t) (with the wind)\r<BR>\n" );
document.write( "\n" );
document.write( "Since both expressions are equal to d we have: \r<BR>\n" );
document.write( "\n" );
document.write( "270*t = 330*(5-t)\r<BR>\n" );
document.write( "\n" );
document.write( "Solve the above for t then calculate the distance d by substituting this value for t in either 1.) or 2.) above.\r<BR>\n" );
document.write( "\n" );
document.write( "Remember the TOTAL distance traveled is 2*d.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );