document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=268733>Question 268733</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do you solve x squared + 10x + 25 all under a radical </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #196913 by </B><A HREF=/tutors/aboutme.mpl?userid=persian52><B>persian52(161)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=persian52><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=persian52><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=196913\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ~(x^(2)+10x+25)\r<BR>\n" );
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document.write( "For a polynomial of the form x^(2)+bx+c, find two factors of c (25) that add up to b (10).  In this problem 5*5=25 and 5+5=10, so insert 5 as the right hand term of one factor and 5 as the right-hand term of the other factor.<BR>\n" );
document.write( "~((x+5)(x+5))\r<BR>\n" );
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document.write( "Combine the two common factors of (x+5) by adding the exponents.<BR>\n" );
document.write( "~((x+5)^(2))\r<BR>\n" );
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document.write( "Remove the parentheses around the expression x+5.<BR>\n" );
document.write( "Answer: x+5\r<BR>\n" );
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document.write( "There you go!&#9734;  </SPAN>\n" );
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